38: What is the molarity of a solution made by dissolving 8.49 g of sodium aceta

Question

38: What is the molarity of a solution made by dissolving 8.49 g of sodium acetate in water and diluting to 750. mL? (molar mass NaC2H3O2 is 82.0 g/mol.)

39: An open-ended mercury manometer is used to measure the pressure exerted by a trapped gas as shown in the figure. Atmospheric pressure is 750. mmHg. What is the pressure (in mmHg or torr) of the trapped gas if h =3 cm?

40: What volume (in mL) of 12 M HCI solution is required to prepare exactly 500. mL of a 0.38 M HCI solution?

50: When a 80 g sample of an alloy at 100.0 oC is dropped into 90.0 g of water at 22.1 oC, the final temperature is 34.0 oC. What is the specific heat of the alloy? (The specific heat of water is 4.184 J/(goC).)

53:
When 193 J of energy are added to a sample of gallium that is initially at 25.0 oC, the temperature rises to 40.0 oC. What is the volume of the sample in cubic centimeter?

Gallium, Ga

specific hear 0.372 J(g^-1)(C^-1)

Density 5.904 (g)(cm^-3)

Explanation / Answer

according to cheg guide lines i can answer only one question

38.

use the molarity formula

molarity (M) = (weight of solute / molar mass of solute ) x 1000 / volume of solvent inmL

here solute is sodium acetate

solvent is water

weight of solute = 8.49

molar mass of solute given is 82.0 g/mol

volume of the solvent = 750 mL

plug in all these values in above equation

M = (8.49 g / 82.0 g/mol ) x 1000 / 750 mL

M = 0.1035 x 1.3333

M = 0.138 mol/L or

M = 0.14 M

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