1. Chloroform, CHCl3, reacts with chlorine, Cl2, to form carbon tetrachloride, C

Question

1. Chloroform, CHCl3, reacts with chlorine, Cl2, to form carbon tetrachloride, CCl4, and hydrogen chloride, HCl. In an experiment 25 grams of chloroform and 25 grams of chlorine were mixed. Which is the limiting reactant? What is the maximum yield of CCl4 in moles and in grams?

2. Respiration, one of the most common chemical reactions on earth.

C6H12O6+6O26CO2+6H2O+energy

in the reaction of 25 grams of glucose with 40 grams of oxygen, what mass of carbon dioxide forms and what mass of reactant excess ?

3. 129.62 grams of silver nitrate (AgNO3) are reacted with 185.34 grams of potassium bromide (KBr) to form solid silver bromide (AgBr) by the reaction:

AgNO3(aq) + KBr(aq) AgBr(s) + KNO3

a. Which reactant is the limiting reagent?

b. How much silver bromide is formed?

Explanation / Answer

1. Reaction,

CHCl3 + Cl2 ---> CCl4 + HCl

moles of CHCl3 = 25 g/119.4 g/mol = 0.21 mol

moles of Cl2 = 25 g/70.906 g/mol = 0.35 mol

Since moles of CHCl3 is lower, this is the limiting reagent

Maximum yield of CCl4 formed = 0.21 mol x 153.82 g/mol = 32.30 g

2. moles of glucose = 25 g/180.156 g/mol = 0.14 mol

moles of O2 = 40 g/32 g/mol = 1.25 mol

moles of O2 needed for complete consumption of glucose = 0.14 x 6 = 0.84 mol

Since moles of O2 is higher than required, glucose is limiting reagent

mass of CO2 formed = 0.14 mol x 6 x 44.01 g/mol = 36.97 g

mass of excess reagent (O2) remained = (1.25 - 0.84) mol x 32 g/mol = 13.12 g

3. moles of AgNO3 = 129.62 g/169.87 g/mol = 0.76 mol

moles of KBr = 185.34 g/119 g/mol = 1.56 mol

a. since moles of AgNO3 is lower. AgNO3 is limiting reagent

b. mass of AgBr formed = 0.76 mol x 187.77 g/mol = 142.70 g

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