Benzene and heptane form a regular solution at T=300K for X_c_6h_5- Xc, h_6 = 0-

Question

Benzene and heptane form a regular solution at T=300K for X_c_6h_5- Xc, h_6 = 0-5 middot For this solution it is found that w=1.48. Using regular solution theory calculate the activity coefficient Calculate delta h_Nnx and delta s_xnx Calculate also delta G_NIIX. Do benzene and heptane mix in equip molar amounts at T=300K? Calculate also the vapor pressure of benzene over this solution assuming the vapor behaves ideally. Assume the vapor pressure of benzene at T=300K is 13330 Pa. How much does this value deviate from the predictions of the ideal solution model (i.e. Raoul's law)?

Explanation / Answer

2) a) For a ideal solution, Molefraction = activity coefficient = 0.5 (For the given solution)

b) For an ideal solution, delta H(mix) = 0, as there are no intermolecular attractions.

delta G(mix) = -work done in the solution = -1.48 kJ

Since, delta G (mix) = delta H (mix) - T delta S (mix)

-1.48*103 = 0 - (300) delta S(mix)

delta S(mix) = 4.93 J/mol.K

c) Vapor pressure of Benxene = P0(benzene) * molefraction

= (13330)(0.5) = 6665 Pa

  

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