Exercise 16.108 Consider a solution that is 2.4×10 2 M in Fe2+ and 1.1×10 2 M in

Q: Exercise 16.108 Consider a solution that is 2.4×10 2 M in Fe2+ and 1.1×10 2 M in

KSP of FeCO3 = 1.5*10^-11 ksp of MgCO3 = 6.82 *10-6 if ksp is less , that will precipitate first so that , Fe^2+ gets precipitation first. part B KSP of FeCO3 = 1.5*10^-11 ksp = s^2 = 1.5*10^-11 solubility s = 3.9*10^-6 M minimum concentration required = 3.9*10^-6 M

ID: 1014302 • Letter: E

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Exercise 16.108

Consider a solution that is 2.4×102 M in Fe2+ and 1.1×102 M in Mg2+.

Part A

If potassium carbonate is used to selectively precipitate one of the cations while leaving the other cation in solution, which cation will precipitate first?

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Part B

What minimum concentration of K2CO3K2CO3 is required to cause the precipitation of the cation that precipitates first?

Express your answer using two significant figures.

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Part C

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Chemistry 106 Summer 2016

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Homework Set #5

Exercise 16.108

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Exercise 16.108

Consider a solution that is 2.4×102 M in Fe2+ and 1.1×102 M in Mg2+.

Part A

If potassium carbonate is used to selectively precipitate one of the cations while leaving the other cation in solution, which cation will precipitate first?

If potassium carbonate is used to selectively precipitate one of the cations while leaving the other cation in solution, which cation will precipitate first? Fe2+ Mg2+

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Correct

Part B

What minimum concentration of K2CO3K2CO3 is required to cause the precipitation of the cation that precipitates first?

Express your answer using two significant figures.

[K2CO3] = M

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Part C

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Explanation / Answer

KSP of FeCO3 = 1.5*10^-11

ksp of MgCO3 = 6.82 *10-6

if ksp is less , that will precipitate first

so that , Fe^2+ gets precipitation first.

part B

KSP of FeCO3 = 1.5*10^-11

ksp = s^2 = 1.5*10^-11

solubility s = 3.9*10^-6 M

minimum concentration required = 3.9*10^-6 M

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Exercise 16.108 Consider a solution that is 2.4×10 2 M in Fe2+ and 1.1×10 2 M in

Exercise 16.108p Consider a solution that is 2.4×10 2 M in Fe2+ and 1.5×10 2 M i

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Exercise 16.108 Consider a solution that is 2.4×10 2 M in Fe2+ and 1.1×10 2 M in

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