What is the volume of hclneutralized in 200 ml sample?? 4 If needed Trial 3 Part

Question

What is the volume of hclneutralized in 200 ml sample?? 4 If needed Trial 3 Part IlI 6. Stomach Acid (HCI) used (mL) 7. Initial Buret Reading (mL) 8. Final Buret Reading (mL) 9 Volume NaOH added (mL) 10 Average Volume NaOH Used (mL) Trial 1 25.0 2 1.54 25.0 1.01 2485 25.53 25 19 2 26 39 26.45 26.39 26.45 Part : Trial 1Trial 2 25.0 1.39 20.9920.25 19.61 9 46219 303 Trial 3 25.0 0.81 11 Volume filtered acid added to flask (mL) B 12 Initial Buret Reading (NaOH) (mL) 9 13 Final Buret Reading (NaOH) (mL:) 0 14 Volumme NaOH Added (mt) 19 45 5 Volume HQI Remaining in sample (ml) 2116 Average HOl Remaining in 25 mL (mb) lume HCINeutralizedbywhole Tablet(mL) periment was prepared at a concentration of 0.15M Using your volume of HCI neutra 1. If the HCt usedi a calculate the mass of active ingredient Cac@3) in the tablet in milligrams

Explanation / Answer

Neutralisation reaction :

HCl + NaOH -------> NaCl + H2O, (ratio = 1:1)

Fro the 25 ml HCl to be neutralised it is required volume of 19.462 ML of NaOH,

and volume of HCl left is 19.382 ml,

so ,25-19.382= 5.618 ml HCl is consumed (neutralised),

i.e for the neutralisation of 5.618 ml HCl it is required 19.382 ml NaOH,

for 25 ml HCl , only 5.618 ml HCl is neutralised,

if 25 ml HCl = 5.618 ml hcl,

then for 200 ml HCl = ?,

BY CROSS MULTIPLYING ,

200*5.618=1123.6/25= 44.944 ML HCl is neutralised ,

FOR whole tablet wt = 1.287 gms which is added to 200 ml acid,

suppose here tablet is basic say NaOH,

SO WE CAN CALCULATE THE MOLES OF NaOH,

MOLES= 1.287/40=0.03217 NaOH,

SO ratio is 1:1, (HCl :NaOH),

IT WILL NEUTRALISED 0.03217 MOLES OF ACID ,

molarity of HCl= moles of solute/volume in L,

MOLARITY OF HCl = 0.03217/0.20 (200/1000=0.20 L),

MOLARITY OF HCl=0.16 M

MASS OF HCl= moles* mol. wt = 0.03217*36.5= 1.174 gms of HCl is neutralised ,

VOLUME = MOLES /MOLARITY,

VOLUME= 0.03217/0.16,

=0.20 L (200 ML),

THE VOLUME OF HCL neutralised by whole tablet is 200 ml HCL i.e (total volume of HCl is neutralised)

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