Household vinegar is a 5% (by volume) solution of acetic acid in water. Assuming

Question

Household vinegar is a 5% (by volume) solution of acetic acid in water. Assuming that the density of your vinegar is 1.0055 g/mL and the density of acetic acid is 1.05g/mL; use the molarity of CH3COOH (0.805M) to determine the volume percent of acetic acid in your vinegar sample. Household vinegar is a 5% (by volume) solution of acetic acid in water. Assuming that the density of your vinegar is 1.0055 g/mL and the density of acetic acid is 1.05g/mL; use the molarity of CH3COOH (0.805M) to determine the volume percent of acetic acid in your vinegar sample.

Explanation / Answer

Molarity =(mass/molar mass)*(1000/V(mL))

Mass = Molarity*molar mass*V(mL)/1000

Mass = 0.805*60*100/1000=4.83g

Volume of 4.83g Acetic acid = mass/density=4.83/1.05 = 4.6mL

Volume percentage of acetic acid in 100mL of 0.805M Vinegar solution =Vaa/Vsol*100

=(4.6mL/100)*100 = 4.6%

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