This is the result This is the solution: 4 0405 REAC Identifying Six Solutions b

Question

This is the result This is the solution:
4 0405 REAC Identifying Six Solutions by Their Interactions Prepared by H. A. Neidig and J. Iskowitz, Lebanon Valley College, and M. L. Gillette, Indiana University Kokomo PURPOSE OF THE EXPERIMENT Identify the ionic compound present in each of six unknown solutions by systematically studying the interactions among the ions. Write chemical BACKGROUND INFORMATION Have you ever heard someone say, "A picture is worth a thousand words"? This phrase means that we would need to use a thousand words to convey the message communicated by a single photograph. To a chemist, a balanced chemical equation is much like a photograph. Such an equation describes a reaction in a concise way, using just a few symbols and numbers. Before we evaluate or try to understand a picture, however, we must know something about the objects in the photograph. In the case of a chemical equation, we must know something about the substances involved before we can fully understand the equation. In this experiment, you will study some ionic compounds. lonic compounds form when the bonding species are ions instead of neutral atoms. lons are chemical species that have either a positive or negative charge. A positively charged ion, called a cation, has fewer electrons than protons in its component atom(s). A negatively charged ion, called an anion, has more electrons than protons in its component atom(s). Metal atoms usually form cations, and non-metal atoms usually form anions. Many anions are polyatomic, which means that they are composed of several bonded non-metal atoms. Anions and cations are attracted and bound to each other because of their opposite electrical charges. For example, potassium bromide is an ionic compound containing potassium ions (K+) and bromide ions (Br). Table 1 on the next page lists the names and formulas of some cations and anions you may study in this experiment. "Learning en 49

Explanation / Answer

Looking at the table already given and comparing our results we would say that,

unknown solutions may have,

11 = B : BaCl2

12 = D : Na2CO3

13 = A : KIO3

14 = E : CuSO4

15 = C : Cu(NO3)2

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