Acetic acid ionized according to the reaction: CH_3COOH (aq) + H_2O(l) H_3O^+ (a

Question

Acetic acid ionized according to the reaction: CH_3COOH (aq) + H_2O(l) H_3O^+ (aq) + CH_3COOH(aq) What is the conjugate acid-base pair? What is the conjugate base-acid pair? Write the expression for K_a (The Law of Mass Action). Find the numerical value of K_a from your Reference Tables. Starting with an initial concentration of 0.100 M acetic acid solution (CH_3COOH), fill out a RICE table for this reaction. Is the small-x-Approximation okay? Determine the equilibrium concentrations of. CH_3COOH H_3O^+ CH_3COO^- Calculate pH and pOH. Calculate pK_a Calculate the percent ionization of acetic acid % Ionization = [CH_3COO^-]_eq/[CH_3COO]o * 100

Explanation / Answer

1) Conjuagate acid of a base is the base that gets protonated with H+ ion.

H3O+ is the conjugate acid base pair with H2O as base.

2) Conjuagate base of an acid is the acid that gets deprotonated.

CH3COO- is the conjugate base acid pair with CH3COOH as acid.

3)

Ka = [H3O+][CH3COO-]/[CH3COOH]

4) Ka = 1.8 x 10-5.

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