student is asked to standardize a solution of sodium hydroxide . He weighs out 0

Question

student is asked to standardize a solution of sodium hydroxide. He weighs out 0.977 g potassium hydrogen phthalate (KHC8H4O4, treat this as a monoprotic acid).

It requires 34.9 mL of sodium hydroxide to reach the endpoint.

A. What is the molarity of the sodium hydroxide solution? _______ M.

This sodium hydroxide solution is then used to titrate an unknown solution of perchloric acid.

B. If 23.8 mL of the sodium hydroxide solution is required to neutralize 17.7 mL of perchloric acid, what is the molarity of the perchloric acid solution? _______ M.

Explanation / Answer

1 mole of KHC8H4O4 reacts with 1 mole of NaOH

A. molarity of NaOH solution = 0.977 g/204.22 g/mol x 0.0349 L = 0.137 M

B. 1 moles of HClO4 (perchloric acid) reacts with 1 mole of NaOH

molarity of HClO4 solution = (0.137 M x 23.8 ml)/17.7 ml = 0.184 M

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