1.Which one shows possible sets of quantum numbers for the last three electrons

Question

1.Which one shows possible sets of quantum numbers for the last three electrons of a N atom at ground state?

I. n l m s

2 0 -1 -1/2

2 0 0 -1/2

2 0 +1 -1/2

II. n l m s

2 1 -1 +1/2

2 1 0 +1/2

2 1 +1 +1/2

III. n l m s

2 0 -1 -1/2

2 0 0 -1/2

2 0 +1 +1/2

iv.n l m s

3 1 +1 +1/2

3 1 0 +1/2

3 1 -1 +1/2

2.The maximum number electrons in an atom that has the following set of quantum numbers is n = 4 l = 2 ml = -2 s = +1/2

0

1

2

6

10

3.Which element is paramagnetic? Li Be He Ar

4.Electrons in an orbital with l = 3 are in a/an

d orbital

f orbital

g orbital

p orbital

s orbital

5.Which element has the following electron configuration? [Kr]5s24d105p3

Sn ,Sb ,Te, Pb ,Bi

Explanation / Answer

1. N = 7 1s22s22p3

P-sub energy level l=1

                          px    py    pz

                         -1     0      +1 all three electrons are enter into clock wise direction spin quntum nuber are +1/2

II. n l m s

2 1 -1 +1/2

2 1 0 +1/2

2 1 +1 +1/2

2.    n = 4 l = 2 ml = -2 s = +1/2

    4d1   one electron is present

3. Li = 3 1s22s1 it contains one unpaired electron. So it is paramagnetic.

4. l=3 for f subenergy level

f-orbital

5. Sb = 51    [Kr]5s24d105p3

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