The following data was found for the reaction, A + B rightarrow Products What is

Question

The following data was found for the reaction, A + B rightarrow Products What is the order of the reaction with respect to reactant B? Zero First Second Third Fourth Given: C_3H_8(g) + 5 O_2(g) rightarrow 3 CO_2(g) + 4 H_2O(l) Delta_r H degree = -2220 kJ, What is the enthalpy change for 6 CO_2(g) + 8 H_2O(I) rightarrow 2 C_3H_8(g) + 10 O_2(g) -1.33 times 10^4 kJ +2220 kJ +370 kJ +4440 kJ +2220 kJ The equilibrium law for the CaO(s) + CO_2(g) CaCO_3(s), is K_c = [CO_2] K_c = [CaCO_3]/([CaO] [CO_2]) K_c = 1/[CO_2] K_c = [CaCO_3]/([CaO] = ([CaO] [CO_2])/[CaCO_3]

Explanation / Answer

14

answer is option B first order

from the table while going from 2---> 3concentration of B is constant but concentration of A is double but rate doesnt change which means with respect to A order is zero

from the table 1---> 2 both concentration of A and B become double rate also become double but we already know that with respect to A zero order.

so the rate increase only because of B

so with respect to B first order

15

multiply the given equation with 2 and reverse it

so option E is the correct answer

16

while writing the equilibrium expression we will not consider the solids. but in the given expression two solids are there so ignore it

answer will be option C

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