A 182-g sample of gold at some temperature was added to 22.1 g of water. The ini

Question

A 182-g sample of gold at some temperature was added to 22.1 g of water. The initial water temperature was 25.0 degree C, and the final temperature was 27.5 degree C. If the specific heat capacity of gold is 0.128 J/g middot K, what was the initial temperature of the gold sample? When 108 g of water at a temperature of 22.5 degree C is mixed with 65.1 g of water at an unknown temperature, the final temperature of the resulting mixture is 47.9 degree C. What was the initial temperature of the second sample of water? A 13.8-g piece of zinc is heated to 98.8 degree C in boiling water and then dropped into a beaker containing 45.0 g of water at 25.0 degree C. When the water and metal come to thermal equilibrium, the temperature is 27.1 degree C. What is the specific heat capacity of zinc?

Explanation / Answer

15. Heat lost by hot zinc = heat gained by gained by cold water

heat = mCpdT

13.8 x Cp[zinc] x (98.8 - 27.1) = 45 x 4.184 x (27.1 - 25)

So,

specific heat of zinc (Cp) = 0.399 J/g.oC

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