Solution Stoichiometry To solve stoichiometry problems, you must always calculat

Question

Solution Stoichiometry To solve stoichiometry problems, you must always calculate numbers of moles. Recall that molarity. M, is equal to the concentration in moles per liter:Mmol/L When solutions of siiver nitrate and potassium chloride are mixed, silver chloride precipitates out of solution according to the equation AgNO3 (aq) + KCI(aq)AgCl(s) + KNO3 (aq) Part A What mass of silver chloride can be produced from 1.66 L of a 0.263 M solution of siliver nitrate? Express your answer with the appropriate units. You did not open hints for this part ANSWER mass of AgCI Part B The reaction described in Part A required 3.61 L of potassium chloride. What is the concentration of this potassium chloride solution? Express your answer with the appropriate units. You did not open hints for this part. ANSWER:

Explanation / Answer

part A: 1 mole AgNO3 prouces 1 mole AgCl

silver nitrate solution volume = 1.66 L

its concentration = 0.263 M

silver nitrate moles = M X V (L) = 0.263 X 1.66 = 0.437 moles

therefore 0.437 moles AgCl was formed

Produced AgCl weight = moles X M. Wt. = 0.437 X 143.32 = 62.57 g

part B: required KCl solution to complete the reaction = 3.61 L

at the completion of reaction, moles of both substrates are same.

KCl moles = AgNO3 moles

M X 3.61 = 0.437

KCl concentration = 0.437/3.61 = 0.121 mol/L (or) M

Stong attraction between solvent as well as solute particles may enhance solubility of solute.

part C: CaCl2 molecules are in less number in CaCl2 solution. Because, CaCl2 is a ionic molecule and dissociates completely into ions.

Best wishes.

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