1. Which metal will have a more explosive react ion with water : one with a high

Question

1. Which metal will have a more explosive react ion with water : one with a high ionization energy or one with a low ionization energy? Why?

2. You have decided to investigate the ionization energies of the following alkali metals: K, Cs, Na, Li, Rb. What trend do you expect to see in their reaction with water? Rank the metals from least explosive to most explosive. Which one of the metals tested do you expect will be the best surface to easily eject electrons?

3. You have decided that you do not need test the alkaline earth metals (second column). Provide the abbreviated electron configuration for your chosen metal from above and the

alkaline earth metal next to it. Using the configurations as reference, justify your decision not to test the metals in the second column.

Solar cells work on the principle of the photoelectric effect: if light of enough energy is shone on a metal, electrons will be ejected and will create a usable current. The energy required to remove an electron from an atom in the gas phase (ionization energy) is directly related to the amount of energy required to eject an electron from a solid surface of that element. https://coraifeartaigh.wordpress.com 2010/04/23/the-photoelectric-effect h.wordpress.com/2010/04/23/the-photoelectric-effect You want to determine the best metal to use for this surface by confirming the trend of ionization energy in the alkali metals (first column).

Explanation / Answer

1.Which metal will have a more explosive react ion with water : one with a high ionization energy or one with a low ionization energy = low ionization energy. As the ionization energy decreases, the valency electrons can easily removed and undergoes chemical reactions more rapidly.

2. From top to bottom in the group metallic nature increases and reactivity also increases.

least explosive to most explosive = Li < Na < K < Rb < Cs.

3.Alkaline earth metals general valency shell electronic configuration = ns2

Be = [He]ns2

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