what is the ph of the mixture made by addition of NaOH solution of 50.0 ml and 0

Question

what is the ph of the mixture made by addition of NaOH solution of 50.0 ml and 0.080 m into a solution of acetic acid of 200 ml and 0.050 solution and mix the two well what is the ph of the mixture made by addition of NaOH solution of 50.0 ml and 0.080 m into a solution of acetic acid of 200 ml and 0.050 solution and mix the two well what is the ph of the mixture made by addition of NaOH solution of 50.0 ml and 0.080 m into a solution of acetic acid of 200 ml and 0.050 solution and mix the two well

Explanation / Answer

pKa = ((CH3COO-)(H+))/(CH3COOH)

(H+) = pKa x (CH3COOH) / (CH3COO-)

= 1.76 x 10 -5 x (0.05)/(0.08)

= 1.1 x 10 -5

pH = -log (H+)

= -log (1.1 x 10 -5)

= 5 log(1.1)

= 4.96

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