1) What is the definition of the Enthalpy of Reaction? A) The amount of heat in
ID: 1006369 • Letter: 1
Question
1) What is the definition of the Enthalpy of Reaction?
A) The amount of heat in kJ released (exothermic) or gained (andothermic) per mole of product.
B) The amount of heat in Joules require to evaporate 1 mole of reactant.
C) The amount of energy released from gaseous expansion during a reaction.
2) Which of the following reactions needs to be reversed to solve for the Heat of Neutralization between Hydrochloric Acid and Ammonia?
A) Hydrochloric Acid + Sodium Hydroxide.
B) Acetic Acid + Sodium Hydroxide.
C) Acetic Acid + Ammonia.
3) What is the molar heat of neutralization (Enthalpy of Reaction) in kJ/mol if 5 moles of HA neutralized 5 moles of BOH and released 7130 J of heat?
4) Calculate the molar heat of neutralization in kJ/mol of the reaction between HA and BOH given the following information:
The temperature change equals 10C,
50 mL of 1 M concentration of Acid
50 mL of 1 M concentration of Base
Heat capacity of the calorimeter is 6.5 J/C.
Remember that the specific heat of water is 4.18 J/gC
5) How much heat is gained (in Joules) by the water where a chemical reaction takes place in 100 mL aqueous solution and has a temperature increase of 12 C?
Explanation / Answer
neutr1) A)
2) A)
3) Molar heat of neutralization = heat / mole
= 7.130/5 = 1.426 KJ
4) dH = mcdt. m = mass, c= specific heat, dt = change in terature
For calorimeter dH = 6.5 × 10 = 65 J
For solution dH = 4.18× 10 = 41.8 J
Total dH = 65 + 41.8 = 116.8 J
= 0.1168 KJ
Mole = 1 mole/L × 0.050 = 0.050 mole
Molar heat of neutralization = 0.1168/0.050 KJ = 2.336 KJ
5) density = 1 g/mL (assumed)
m = 100 g
heat of neutralization dH = mcdt
= 4.18×100×12
= 5016 J
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