1. Based on the solubility rules, which one of the following compounds should be

Question

1. Based on the solubility rules, which one of the following compounds should be insoluble in water?
A) FeCl2
B) AgBr
C) MgBr2
D) NaCl
E) ZnCl2

2. Using the redox reaction below determine which element is oxidized and which is reduced

4NH3 + 3Ca(ClO)2 --> 2N2 + 6H2O + 3CaCl2

A) H is oxidized and N is reduced
B) Cl is oxidized and O is reduced
C) N is oxidized and O is reduced
D) Cl is oxidized and N is reduced
E) N is oxidized and Cl is reduced

3. What mass of C6H12O6 (glucose) is needed to prepare 150. mL of a 0.650 M solution of glucose in water?
A) 293 g
B) 52.7 g
C) 125 g
D) 0.293 g

Explanation / Answer

1) B: AgBr

As per solubility rules all halides, Cl-, Br- and I- are soluble in water except those of Ag+, Pb2+ and (Hg2)2+

2) E

Oxidation state of N changes from -3 in NH3 to 0 in N2, therefore N loses electrons and gets oxidised

oxidation state of Cl changes from +1 in Ca(ClO)2 to -1 in CaCl2, therefore Cl gains electrons and gets reduced.

3) M = moles/vol

moles of glucose = M * V = 0.650 * .150 = 0.0975 moles

Moles of glucose = mass of glucose/mol wt of glucose

mass of glucose = moles* mol wt = 0.0975 mol * 180 gmol = 17.55 g

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.