12, 7. In a study of the decomposition of nitrous oxide at 565 oC N20 (g) N2 (g)

Question

12, 7.

In a study of the decomposition of nitrous oxide at 565 oC N20 (g) N2 (g) O2 (g) the following data were obtained: N20], M 1.11 0.278 0.555 2.22 478 seconds 1.44x105 3.34x103 Hint: It is not necessary to graph these data. (1) The observed half life for this reaction when the starting concentration is 2.22 M is and when the starting concentration is 1.11 M is (2) M-1 s The average A(1/LNOD At from 0 s to t 478 s is The average A(1/IN20D At from t 478 s to t 1.44x105 s is -1 s MT (3) Based on these data, the rate constant for this order reaction is -1 C-1 MT

Explanation / Answer

from the data

1) when 2.22 M, half life = 478 sec

       1.11 M , half life = 1.44*10^3 sec

2) k = 1/t1/2a

       = 1/(478*2.22) = 9.4*10^-4 M-1.S-1

     K = 1/(962*1.11) = 9.4*10^-4 m-1.s-1

3) Second order reaction is 9.4*10^-4 m-1.s-1

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