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More information is needed to solve the problem. In the reaction below. deltaH d

ID: 1005419 • Letter: M

Question

More information is needed to solve the problem. In the reaction below. deltaH degree F it zero for Ni(s) + 2CO(g) + 2PF_3(g) rightarrow NI(CO)_2(PF_3)_2 (1) Ni (g) CO(g) F_3 (g) Ni(CO)_2(PF_3)_2(l) both CO (g) and PF_3 (g) For the species in the reaction below, deltaH degree F is zero for. Co(s) H_2(g) PF_3(g) HCo(PF_3)_2 (1) both Co(s) and H_2(g) For which one of the following equations is deltaHdegree_rxn equal to deltaH degree F for the product? For which one of the following reactions b the value of deltaHdegree_rxn equal to deltaH degree F for the product? For Which one of .he following reaction, i, ehe value of deltaH degree equal to deltaHdegree, for the Product?

Explanation / Answer

28) A

The standard enthalpy of formation for an element in its standard state is zero, because Elements in their standard state are not formed.

29) A

30) A

For this type of questions You know the definition of the "heat of formation." The heat of formation is the H when one mole of the compound is made from the elements in their standard states and also know what the standard states of the elements are.

in given Choices

A---->Yes it is the answer Because XeF4 is formed from its elements

B-----> No, Because CH4 is not an element

C-----> No, -----------O3 is not an element

D----->No, -------------CO is not an element

E-------> No---------Diamond is not a standered state of carbon

similar protocol will follow for remaining questions

31) D

32) A

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