Exercise 17.12 Given the values of H rxn, S rxn, and T below, determine S univ.

Question

Exercise 17.12

Given the values of Hrxn, Srxn, and T below, determine Suniv.

Part A

Hrxn= 89 kJ , Srxn= 146 J/K , T= 290 K

Express your answer using two significant figures.

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Part B

Hrxn= 89 kJ , Srxn= 146 J/K , T= 756 K

Express your answer using two significant figures.

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Part C

Hrxn= 89 kJ , Srxn= 146 J/K , T= 290 K

Express your answer using two significant figures.

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Part D

Hrxn= 89 kJ , Srxn= 146 J/K , T= 410 K

Express your answer using two significant figures.

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Part E

Predict whether or not the reaction in part A will be spontaneous.

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Part F

Predict whether or not the reaction in part B will be spontaneous.

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Part G

Predict whether or not the reaction in part C will be spontaneous.

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Part H

Predict whether or not the reaction in part D will be spontaneous.

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Exercise 17.12

Given the values of Hrxn, Srxn, and T below, determine Suniv.

Part A

Hrxn= 89 kJ , Srxn= 146 J/K , T= 290 K

Express your answer using two significant figures.

Suniv =   J/K  

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Part B

Hrxn= 89 kJ , Srxn= 146 J/K , T= 756 K

Express your answer using two significant figures.

Suniv =   J/K  

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Part C

Hrxn= 89 kJ , Srxn= 146 J/K , T= 290 K

Express your answer using two significant figures.

Suniv =   J/K  

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Part D

Hrxn= 89 kJ , Srxn= 146 J/K , T= 410 K

Express your answer using two significant figures.

Suniv =   J/K  

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Part E

Predict whether or not the reaction in part A will be spontaneous.

Predict whether or not the reaction in part A will be spontaneous. spontaneous nonspontaneous

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Part F

Predict whether or not the reaction in part B will be spontaneous.

Predict whether or not the reaction in part B will be spontaneous. spontaneous nonspontaneous

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Part G

Predict whether or not the reaction in part C will be spontaneous.

Predict whether or not the reaction in part C will be spontaneous. spontaneous nonspontaneous

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Part H

Predict whether or not the reaction in part D will be spontaneous.

Predict whether or not the reaction in part D will be spontaneous. spontaneous nonspontaneous

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Explanation / Answer

Part A - Delta S universe = Delta S(system) + delta S (surrounding)

= delta S (reaction) - delta H(reaction)/T

We have delta S reaction, delta H reaction and Temperature with us.

Substituing these values, we can find delta S universe.

Delta Suniverse = 146 J/K - (89000J/ 290 K)

= 146 - 306.89

= -160.89

Similarly , we solve for rest of the parts.

PART B - Delta S universe = 146- (89000/ 290)

= 146 - 117.72

= 28.28 J/K

PART C - Delta Suniverse = -146 - (89000/290)

= -146 - 306.89

= -452.89 J/K

PART D - Delta Suniverse = 146- (-89000/ 410)

= 146- (-217.07)

= 146+ 217.07

= 363.07 J/K

Now, we need to predict spontaneity of a reaction.

If delta Suniverse is positive, then the reaction is spontaneous and if it is negative, then reaction is non spontaneous.

ANS E- Since delta S universe in part A is negative, so reaction is non spontaneous.

ANS F - Here, Delta S universe is positive, so reaction is spontaneous.

Similarly,

ANS G - Non spontaneous

ANS H - Spontaneous

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