Cyclohexene 20ml 0.20 moles 0.20 moles Water 8ml 0.44 moles | Concentrated Sulfu

Question

Cyclohexene 20ml 0.20 moles 0.20 moles Water 8ml 0.44 moles | Concentrated Sulfuric acid 16ml 0.30 moles Additional information: Boiling points of Azetrope Mixtures Cyclohexene water azetrope 71 degree Celsius Cyclohexane water azetrope 98 degree Celsius Given theoretical yield and quantities of reactants in moles. From these quantities, determine limiting reactant. Convert moles cyclohexanol to milliliters (moles rightarrow grams rightarrow milliliters) Mole ratio: For all reactants - cyclohexene, water and sulfuric acid Determine "Theoretial value" Calculate "Used column" rightarrow Moles reactant/moles limiting reactant

Explanation / Answer

During cyclohexene to cyclohexanol conversion, acid is excess in quantity so cyclohexene is the limiting reagent.

0.2 moles of cyclohexexne theoritically produces 0.2 moles of cyclohexanol

Therefore, cyclohexanol produced = 0.2 X 100.16 = 20.03 gr

Volume of cyclohexanol obtaines = wt./density = 20.03/0.962 = 20.82 mL

Mole ratio of all reactants,

for cyclohexene = moles of cyclohexene/ total moles = 0.2/0.94 = 0.213

for sulpuric acid = moles of sulpuric acid/ total moles = 0.44/0.94 = 0.468

for water = moles of water / total moles = 0.3/0.94 = 0.319

best wishes.

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