Equilibrium Concentrations for a Simple Addition Reaction At a certain temperatu

Question

Equilibrium Concentrations for a Simple Addition Reaction At a certain temperature K-1.10x103 for the reaction Fe3+(aq) + SCN'(aq) FeSCN2+ (aq) 1.90x101 mol of Fe(NO3)s is added to 8.60x101 L of 2.33x102 M KSCN. Neglecting any volume change and assuming that all species remain in solution Calculate the equilibrium concentration of Fe3 (in mol/L). 1.98x10-1 mol/L 1 pts ou are correct. Your receipt no. is 157-9206 Previous Tries Calculate the equilibrium concentration of SCN" (in mol/L) ptsmol/iL 1 pts 000320 Submit Answer Incorrect. Tries 5/8 Previous Tries Calculate the equilibrium concentration of FeSCN2+ (in mol/L). 2.31x10-2 mol/L 1 pts

Explanation / Answer

lets write the expression for k

k = [FeSCN2+] / [Fe3+] [SCN-]

from part -1 we know the equilibrium concentration of Fe3+ = 0.198 mol/L

from part 3 equilibrium concentration of FeSN2+ = 0.0231 mol / L0.0231

1.10 x 103  = [0.0231] / [0.198] [SCN-]

[SCN-] = 0.0231 / 217.8

[SCN-] = 0.000106 = 1.06 x 10-4 mol / L

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