GOB CHEM 120a CP1 Summer 2016 CHQuestion 21 x previous21 of 40 next Question 21

Question

GOB CHEM 120a CP1 Summer 2016 CHQuestion 21 x previous21 of 40 next Question 21 Part A A scuba diver 40 ft below the ocean surface inhales 70.0 mL of compressed air from a scuba tank at a pressure of 2.50 atm and a temperature of 6 C What is the pressure of the air, in atm, in the lungs when the gas expands to 170.0 mL at a body temperature of 37 °C and the amount of gas remains constant? You may want to reference ( pages 303-304) Section 8.5 while completing this problem Express the pressure in atmospheres to three significant figures.

Explanation / Answer

P1 = 2.50 atm

V1 = 70 mL

T1 = 6 + 273 = 279 K

P2 = ?

V2 = 170 mL

T2 = 170 + 273 = 443 K

P1 V1 / T1 = P2 V2 / T2

2.50 x 70 / 279 =P2 x 170 / 443

P2 = 1.63 atm

pressure = 1.63 atm

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