when balancing equation in acidic conditions identify coefficient for h2o to+br2

Question

when balancing equation in acidic conditions identify coefficient for h2o to+br2
Number 2. 6 +2, -1 d. -2, +1 e. None of the above are correct 2. When balancing the equation below in acidic conditions, identify the coefficient for H20? Ti +Br2 TiO+2 + Br" (ACIDIC) a. 4 b. 2 c. e. 3. Using the metal activity series below, which metal is the WEAKEST reducing agent? Ca (sCa2 (aq)+2e Al (sA (aq) +3e Zn (s)Zn2+ (aq) + 2e Fe (s) + Fe2+ (aq) + 2e. Cu (s)-- Cu2+ (aq) + 2e. Ag (s)--+ Ag+ (aq) + 1e. Au (s)Au* (aq) +3e a. Ca b. Zn c. d. Au e. K A 6.21 g sample of iron is initially at 25 C. After 153 J of heat is added to the object, temperature? (Specific heat capacity of iron is 0.450 J/g·°C) 80. C b. 30. C c. 41 C 145 e. 22 C

Explanation / Answer

Given unbalanced redox reaction

Ti + Br2 -------------> TiO2+ + Br-

Here Ti oxidizes from 0 (in Ti) to +4 (in TiO2+)

Br2 reduced from 0 (in Br2) to -1 in Br-.

Let us write half-cell reactions,

Oxidation Half Reaction (OHR) :Ti -------------> TiO2+ .

Reduction Half Reaction (RHR): Br2 -------------> Br- .

Let us balance OHR and RHR separately by following following steps,

1) Balancing of atoms other O and H,

OHR: No need they are allready.

RHR: Br2 -------------> 2 Br- .

2) Balancing of O and H.

O balnced by adding H2O equal to the deficiency on o deficient side and then H+ added to H deficient side to balanced H atoms.

OHR: Ti + H2O -------------> TiO2+ +2H+

RHR: No need as no H or O involved.

3) Balncing of charge by adding appropriate number of electrons on side with less -ve or excess +ve charge.

OHR: Ti + H2O -------------> TiO2+ +2H+ + 4e-

RHR: Br2 + 2e -------> 2 Br- .

4) Charge balance needs RHR multiplied by 2 hence,

2 x RHR : 2 Br2 + 4e--------> 4 Br- .

We have finally balanced OHR and RHR as,

OHR: Ti + H2O -------------> TiO2+ +2H+ + 4e-

RHR:2Br2 + 4e ------->4 Br- .

Let us add these balance half reaction,

4 e get cancelled mutually hence not written,

Ti + H2O + 2Br2 -------------> TiO2+ + 2H+ + 4Br-.

Hence the balanced redox reaction.

In balanced reaction,

Coefficient of H2O is 1 and of Br2 is 2.

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