An elemental analysis of a compound containing carbon, hydrogen and nitrogen was

Question

An elemental analysis of a compound containing carbon, hydrogen and nitrogen was known to have a C:H ratio of 3: 4 and a C:N ratio of 6:1. What is the empirical formula of the compound? CHN C_3H_4N_6 C_6H_8N_6 C_6H_8N 563.2 milligrams of Ca_3(PO_4)_2 corresponds to how many millimoles of Ca_3(PO_4)_2? 1816 millimoles 181.6 millimoles 18.16 millimoles 1.816 millimoles How many moles of oxygen atoms (O) are there in 1.34 moles of manganese (VII) oxide (MM = 221.81)? 34.3 moles 9.38 moles 2.68 moles 0.191 moles

Explanation / Answer

For number 9:

The answer will be d), as carbon and nitrogen do share a 6 on 1 ratio, and carbon and hydrogen share a 6:8 ratio, which simplified is a 3:4 ratio.

For number 10:

Molar mass = 310.17 g/mol = 310.17 mg/mmol

We have 563.2 milligrams:

563.2 mg * (1mmol / 310.17 mg) = 1.8158 mmol, letter d)

For number 11:

Each mole of oxide has 7 moles of oxygen:

7 * 1.34 = 9.38 moles of O

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