There is FOUR parts to this question. (A, B, C, & D) ANSWER ALL PARTS. SHOW YOUR
ID: 1000054 • Letter: T
Question
There is FOUR parts to this question. (A, B, C, & D) ANSWER ALL PARTS. SHOW YOUR WORK, CLEARLY!
Will a precipitate of Callo3)2 form when 400. mL of 0.015 M CaCl2 M of are added to 300. mil. of a precipitate of CaflO3)2 form when 4 0.15 M NalO3? .5 The Ksp of Ca(l03)2 is 6.17 x10 a) What is the reaction for the solubility of Ca(lO3)2(s)? ) What is the reaction for the solubility of Calloso b) Given that the final volume is 700 mL, dletermine the concentrations of [Ca2 1 and [10l. of[C.2+1 and 110), c) Calculate Qto determine if Ca(IO3)/2 precipitates. (s) in pure water?Explanation / Answer
CaCl2 + 2NaIO3 ----> Ca(IO3)2 + 2NaCl the kps of Ca(IO3)2 is 6.47x10-5
nCaCl2 = C1 x V1 = 0.4l x 0.015mol/l = 6x10-4mol CaCl2
nNaIO3 = C2 x V2 = 0.3l x 0.15mol/l = 4.5x10-2 NaIO3
the limit reagent is the CaCl2 because he reacction whit 1.2x10-3mol of NaIO3 and i have 4.5x10-2 NaIO3
the mol of Ca(IO3)2 formed are = to mol of CaCl2 =) nCa(IO3)2 = 1.2x10-3mol
a) Ca+2 + 2IO3- -----> Ca(IO3)2(s) [Ca+2][IO3]2 = Kps
b) to begining before the reacction nCa+2 = nCaCl2 = 6x10-4mol nIO3- = nNaIO3 = 4.5x10-2mol
[Ca+2] = 6x10-4mol /0.7l = 8.57x10-4M and the [IO3] =4.5x10-2mol / 0.7l = 6.48x10-2M
C)
late of reaction [Ca+2] = [Ca+2]o -X and [IO3] = [IO3]o - X as the Kps control the concentrations in solutions
[Ca+2][IO3]2 = Kps = [Ca+2]o -X ([IO3]o - X)2 = Kps as the Kps is little Kps = 6.47x10-5 and the [IO3] > [Ca+2] we cant say than the concentration of Ca is verry little and for so X is negligible so get
[Ca+2][IO3]2 = Kps =) [Ca+2] = Kps/[IO3]2 = 6.47x10-5 mol3/(6.48x10-2M)2 =) [Ca+2] = 1.5x10-2M and i have a fewer than in solution therefore all specs are present in solution dont presipite
D) in water pure [Ca+2][IO3]2 = Kps we say than S = to solubility of sustances and replacing get
[S][S]2 = Kps =) Kps = [S]3 so the S = (Kps)1/3 = ( 6.47x10-5 mol3)1/3 = 4x10-2M
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.